About the Company:
KLA-Tencor Corporation (NASDAQ: KLAC), a leading provider of process
control and yield management solutions, partners with customers around the
world to develop state-of-the-art inspection and metrology technologies. These
technologies serve the semiconductor, data storage, LED, photovoltaic, and
other related nanoelectronics industries. With a portfolio of industry-standard
products and a team of world-class engineers and scientists, the company has
created superior solutions for its customers for over 30 years. Headquartered
in Milpitas, California, KLA-Tencor has dedicated customer operations and
service centers around the world. Additional information may be found at
www.kla-tencor.com
Job Description: Applications Development Engineer
Applications Engineer will be responsible for:
- Product penetration/adoption and process optimization at customer facilities in fabs. This includes gaining expertise on KLA-Tencor equipment and customers semiconductor fabrication processes and applying them to solve mission-critical production problems. Apps engineering roles also include training customers and other apps engineers, handling/driving local apps escalation process, investigating customer technical needs/problems and providing solutions, conducting final acceptance, demonstrating products, and understanding competitive situations, methodology, and performance group analysis. Report technology development and new applications to Marketing. Support pre-sale and post-sale activities.
- Characterization of new systems and features. This includes designing and conducting experiments, collecting data, publishing results and recommendations in the form of applications notes, best-known methods or characterization studies.
Selection Process
Resume Shortlist > Test > Group Discussion > Technical Interview > Case study and developing algorithm > interview based on Case study > behavioral + hr + guess estimate interview > HR Interview
Sample Test Questions with answer:
There are 15 questions (objective type and fill the answer) in 1 hr.
A. 20
B. 15
C. 10
D. 5
E. None of these
Solution:
% of married = 85%
% of phone = 70%
% of phone = 70%
% of car = 75%
% of house = 80.
Therefore,
% of not married = 15%
% of not having phone = 30%
% of not owning car = 25%
% of not having house = 20%
So, % of not having any of these things = 15 +25+ 30 + 20 = 90%
So, % of people having all = 100 -90 = 10%
Thus, people = 10
(2) If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour?
A.450
B.451
C.350
D.425
Solution:
There are 60 minutes in an hour. In ¾ of an hour, there are (60 * ¾) minutes = 45 minutes. In
¾ of an hour there are (60 * 45) seconds = 2700 seconds. Light flashed for every 6 seconds. In 2700
seconds 2700/6 = 450 times. The count starts after the first flash, the light will flash 451 times in ¾ of an
hour
(3) A software engineer has the capability of thinking 100 lines of code in five minutes and can type 100
lines of code in 10 minutes. He takes a break for five minutes after every ten minutes. How many
lines of codes will he complete typing after an hour?
A.250
B.220
C.150
D.200
Explanation: To understand it will break one hour in 12 segments of five minutes.
1st 5 Minutes = Thinks
2nd 5 minutes = Write.
3rd 5 minutes = Rest.
4th 5 Minutes = Write. [Because he can write up to 10 minutes if he thinks for 5 minutes.]
5th 5 minutes = Think. [He has completed 10 minutes of writing so he has to think.]
6th 5 minutes = Rest.
7th 5 minutes = Write.
8th 5 minutes = Write.
9th 5 minutes = Rest.
10th 5 minutes = Think.
11th 5 minutes = Write.
12th 5 minutes = Rest. [He has completed his 10 minutes of working. 5 minutes thinking + 5 Minutes writing.)
So, in one hour he will write 250 lines of codes.
1st 5 Minutes = Thinks
2nd 5 minutes = Write.
3rd 5 minutes = Rest.
4th 5 Minutes = Write. [Because he can write up to 10 minutes if he thinks for 5 minutes.]
5th 5 minutes = Think. [He has completed 10 minutes of writing so he has to think.]
6th 5 minutes = Rest.
7th 5 minutes = Write.
8th 5 minutes = Write.
9th 5 minutes = Rest.
10th 5 minutes = Think.
11th 5 minutes = Write.
12th 5 minutes = Rest. [He has completed his 10 minutes of working. 5 minutes thinking + 5 Minutes writing.)
So, in one hour he will write 250 lines of codes.
(4) A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
[A]. Rs. 375
[B]. Rs. 400
[C]. Rs. 600
[D]. Rs. 800
(5) You have 20 white and 13 black balls in a bag. You pull out 2 balls one after another. If the balls are of same color, then you replace them with a white ball – but if they are of a different color, you replace them with a black ball. Once you take out the balls, you do not put them back in the bag – so the balls keep reducing. What would be the color of the last ball remaining in the bag?
Black
(6) The probability of a car passing a certain intersection in a 20-minute window is 0.9. What is the probability of a car passing the intersection in a 5-minute window? (Assuming a constant probability throughout)
0.4377
Explanation:
Let’s start by creating an equation. Let x be the probability of a car passing the intersection in a 5-minute window.
Probability of a car passing in a 20-minute window = 1 – (probability of no car passing in a 20-minute window)
Probability of a car passing in a 20-minute window = 1 – (1 – probability of a car passing in a 5 minute window)^40.9 = 1 – (1 – x)^4
(1 – x)^4 = 0.1
1 – x = 10^(-0.25)
x = 1 – 10^(-0.25) = 0.4377
(7) Let N be the greatest number that will divide 1305, 4665, and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
(A) 4
(B) 5
(C) 6
(D) 8
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
(8) 5+2+2=101041, 9+2+4=183662, 8+6+3=482466, 5+4+5=202504 then find 7+2+5=?
Answer : 143542
Explanation:
First 2 digits are the multiplication of first and second digit of Que i.e. 7x2=14
Next 2 digits are the multiplication of second and third digit of Que i.e. 7x5=35
Last 2 digits :
Step 1- add first and last digit of Que i.e. 7+5=12
Step 2- now multiply it with middle digit of Que i.e. 12x2=24
Step 3- now reverse the order of no. So, 42 and append it.
So, the final answer is 143542
Next 2 digits are the multiplication of second and third digit of Que i.e. 7x5=35
Last 2 digits :
Step 1- add first and last digit of Que i.e. 7+5=12
Step 2- now multiply it with middle digit of Que i.e. 12x2=24
Step 3- now reverse the order of no. So, 42 and append it.
So, the final answer is 143542
(9) In what ratio must a grocer mix two varieties of sugar worth 120 per kg and 180 a kg so that by selling the mixture at 205 per kg, he could gain 25%?
4:11
(10) Four people need to cross a rickety bridge at night. Unfortunately, they have only one torch and the bridge is too dangerous to cross without one. The bridge is only strong enough to support two people at a time. Not all people take the same time to cross the bridge. Times for each person: 1 min, 2 mins, 7 mins and 10 mins. What is the shortest time needed for all four of them to cross the bridge?
(A) 17
(B) 18
(C) 20
(D) 21
Explanation:
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins
(11) A, B, and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.
[A]. Rs. 1900
[B]. Rs. 2660
[C]. Rs. 2800
[D]. Rs. 2840
Explanation:
For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 - 370) = Rs. 7030.
Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)
= 39000 : 42000 : 30000 = 13 : 14 : 10
B's share = Rs.7030 x14 /37 = Rs. 2660.
(12) Four heat-seeking missiles are initially placed at the corners of a square with side length s. Each missile flies at a constant speed toward the missile on its left. Describe the path each missile takes until it collides with the rest in the square's center. What is this path's length?
They will meet at the center Finally.
(13)
(14)
(15)
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