Sunday 20 May 2018

Radiation-II


THE VIEW FACTOR/SHAPE FACTOR


It is a purely geometric quantity and is independent of the surface properties and temperature. It is also known as configuration factor and angle factor.

The view factor from a surface i to a surface j is denoted by Fi → j or just $F_{ij}$, and is defined as
$F_{ij}$ = the fraction of the radiation leaving surface i that strikes surface j directly
\[F_{ij} = \frac{Q_{ij}}{Q_i}\]
Here,            $Q_{ij}$ =  fraction of rate of energy leaving surface i reaching surface j
                    Qi = Rate of total energy radiated by surface i

  • In general, 0 ≤ $F_{ij}$ ≤ 1.
  • The view factor from a surface to itself is zero for plane or convex surfaces and nonzero for concave surfaces.


Reciprocity Relation

\[\boxed{A_1F_{12} = A_2F_{21}}\]

Summation Rule

The sum of the view factors from surface i of an enclosure to all surfaces of the enclosure, including to itself, must equal unity.
\[\boxed{\sum^N_{j =1} F_{ij}  =1}\]

$F_{11} = 0$

$F{11} + F_{12} = 1$   (Summation Rule)

hence $F_{12} = 1$

$A_1F{12} = A_2F_{21}$   (Reciprocity Rule)

$F_{21} = \frac{A_1}{A_2}$

$F_{21} + F_{22} = 1$   (Summation Rule)  

$F_{22} = 1 - F_{21} = 1 - \frac{A_1}{A_2}$




Superposition Rule


The view factor from a surface i to a surface j is equal to the sum of the view factors from surface i to the parts of surface j. 

Note : The reverse of this is not true.

 \[F_{1(23)} = F_{12} + F_{13}\]






Symmetry Rule


This Rule can be expressed as two (or more) surfaces that possess symmetry about a third surface will have identical view factors from that surface.






The Crossed-Strings Method



View Factors between Infinitely Long Surfaces is given by
\[F_{12} = \frac{(L_5 +L_6) -(L_3 + L_4)}{2*L_1}\]

\[F_{ij} = \frac{\sum (Crossed \quad Strings) - \sum (Uncrossed \quad Strings)}{2*(String \quad on \quad surface 'i')}\]






Net Radiation Heat Transfer to or from a Surface


Net Energy Leaving a Surface

The net energy leaving from the surface will be equal to the difference between the energy leaving a surface and the energy received by a surface 
\[Q_i = A_i(J_i -G_i)\]
\[J = ε E_b + ρG\]
If Surface is opaque, ρ = 1 – α 

J = ε Eb + (1 – α) G



we get,   $Q_i = \frac{E_b - J_i}{R_i}$ and $R_i = \frac{1-ε_i}{A_iε_i}$ is the surface resistance to the radiation.

Net Exchange Between Surfaces


The net rate of radiation heat transfer from surface i to surface j can be expressed as
\[Q_{ij} = A_iJ_iF_{ij} - A_jJ_jF_{ji}\]
\[Q_{ij} = \frac{J_i - J_j}{R_{ij}}\]
where $R_{ij}= \frac{1}{A_iF_{ij}}$ is the space resistance to the radiation.

Electrical circuit representation of two surfaces which can see each other nothing else


Total resistance      $R_t = \frac{1-ε_1}{ε_1A_1} + \frac{1}{A_1F_{12}} + \frac{1-ε_2}{ε_2A_2}$
\[Q_{12} = \frac{E_{b1} - E_{b2}}{R_t}\]

Radiation Shields

Assume two flat infinite long flate surfaces 1 and 2 have N shields in between.


Net Heat Transfer without any shield:
\[Q = \frac{A \sigma (T_1^4 - T_2^4)}{\frac{1}{ε_1} + \frac{1}{ε_2} -1}\]

Net Heat transfer with N shields
\[Q = \frac{A \sigma (T_1^4 - T_2^4)}{(\frac{1}{ε_1} + \frac{1}{ε_2} -1) + \sum^N_{j=1}(\frac{1}{ε_{j,1}} + \frac{1}{ε_{j,2}} -1) }\]


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If you have any query, ask in comments.

1 comment:

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